Module 1: Mathematics — EASA Part-66 Category A (Piston Engine)

1. Module Overview

Module 1 of the EASA Part-66 basic knowledge syllabus provides the mathematical foundation required for aircraft maintenance certifying staff. For Category A (Piston Engine) licence holders, the emphasis is on practical, applied mathematics rather than abstract theory. The module covers arithmetic, algebra, geometry, and introductory statistics — all essential for interpreting maintenance manuals, performing weight and balance calculations, converting units, and applying formulas in daily maintenance tasks.

The knowledge levels for Category A require:

Level 1: A familiarisation with the principal elements of the subject

Level 2: A general knowledge of the theoretical and practical aspects, with the ability to apply basic formulas and perform standard calculations

This module is assessed as part of the composite examination for the Category A licence, and the mathematical skills acquired here are applied throughout all subsequent modules, particularly Module 3 (Electrical Fundamentals), Module 6 (Materials and Hardware), and Module 13 (Aeroplane Structures and Systems).

2. Arithmetic Fundamentals

2.1 The SI System of Units

The International System of Units (SI) is the standard measurement system used throughout aviation maintenance documentation, including the EASA regulatory framework. Certifying staff must be proficient in both SI and imperial units, as legacy aircraft documentation frequently uses imperial measurements.

Base SI Units Relevant to Aircraft Maintenance:

Quantity	Unit	Symbol
Length	metre	m
Mass	kilogram	kg
Time	second	s
Electric current	ampere	A
Temperature	kelvin	K

Derived SI Units Commonly Used:

Quantity	Unit	Symbol	Equivalent
Force	newton	N	kg·m/s²
Pressure	pascal	Pa	N/m²
Energy	joule	J	N·m
Power	watt	W	J/s
Torque	newton-metre	N·m	—
Frequency	hertz	Hz	s⁻¹

2.2 Metric Prefixes

The metric system uses prefixes to denote multiples and submultiples of base units. These are essential for converting between millimetres, metres, and kilometres, or between grams and kilograms.

Prefix	Symbol	Multiplier
giga	G	10⁹
mega	M	10⁶
kilo	k	10³
hecto	h	10²
deca	da	10¹
deci	d	10⁻¹
centi	c	10⁻²
milli	m	10⁻³
micro	µ	10⁻⁶
nano	n	10⁻⁹

Example: 1 metre = 1000 millimetres = 100 centimetres = 0.001 kilometres

2.3 Unit Conversion

Unit conversion is one of the most frequently applied skills in aircraft maintenance. Incorrect conversions can lead to serious errors in torque application, fuel calculations, and structural measurements.

Common Conversion Factors:

From	To	Multiply By
metre (m)	millimetre (mm)	1000
millimetre (mm)	metre (m)	0.001
kilogram (kg)	pound (lb)	2.20462
pound (lb)	kilogram (kg)	0.453592
litre (L)	imperial gallon (gal)	0.219969
imperial gallon (gal)	litre (L)	4.54609
newton-metre (N·m)	pound-foot (lb·ft)	0.737562
pound-foot (lb·ft)	newton-metre (N·m)	1.35582
kilogram-force metre (kgf·m)	newton-metre (N·m)	9.80665
newton-metre (N·m)	kilogram-force metre (kgf·m)	0.101972

Worked Example — Torque Conversion:

A maintenance manual specifies a torque of 25 N·m. Convert this to pound-feet.

25 N·m × 0.7376 lb·ft/N·m = 18.44 lb·ft

Worked Example — Fuel Volume Conversion:

A maintenance log records 12.5 imperial gallons of fuel consumed. Convert to litres.

12.5 gal × 4.546 L/gal = 56.825 L

2.4 Fractions, Decimals, and Percentages

Fractions and decimals appear throughout maintenance calculations, particularly when working with resistor networks, fuel mixtures, and tolerance specifications.

Operations with Fractions:

Addition/Subtraction: Find a common denominator first

Multiplication: Multiply numerators and denominators

Division: Multiply by the reciprocal

Worked Example — Parallel Resistances:

Two resistors, R₁ = 12 Ω and R₂ = 18 Ω, are connected in parallel.

1/R_total = 1/12 + 1/18 = (3 + 2)/36 = 5/36

R_total = 36/5 = 7.2 Ω

Percentages:

A percentage is a fraction with a denominator of 100. Percentages are used in:

Tolerance calculations

Performance calculations

Mixture ratios

3. Algebra

3.1 Linear Equations

Linear equations are the most common algebraic form encountered in maintenance documentation. Solving for an unknown variable is a fundamental skill.

Worked Example:

Solve for x: 3x − 7 = 11

Step 1: Add 7 to both sides → 3x = 18

Step 2: Divide both sides by 3 → x = 6

Key Principle: Whatever operation is performed on one side of the equation must be performed on the other side to maintain equality.

3.2 Rearranging Formulas

Maintenance manuals often provide formulas in one form, but the technician may need to solve for a different variable.

Common Formula Rearrangements in Aircraft Maintenance:

Ohm's Law: V = I × R

Solve for I: I = V/R

Solve for R: R = V/I

Electrical Power: P = I² × R

Solve for I: I = √(P/R)

Solve for R: R = P/I²

Moment Calculation: M = F × d

Solve for d: d = M/F

Solve for F: F = M/d

Worked Example — Centre of Gravity:

Total moment = 125,000 kg·mm, total weight = 2,500 kg

CG location = Total moment / Total weight = 125,000 / 2,500 = 50 mm

3.3 Ratios and Proportions

Ratios express the relationship between two quantities. In aviation, ratios appear in:

Compression ratios

Gear ratios

Mixture ratios

Aspect ratios

Worked Example — Fuel Consumption:

An aeroplane consumes fuel at 45 litres per hour. Fuel density is 0.8 kg/litre. Calculate consumption in kg/minute.

Step 1: Hourly mass consumption = 45 L/h × 0.8 kg/L = 36 kg/h

Step 2: Convert to per minute = 36 kg/h ÷ 60 min/h = 0.6 kg/min

3.4 Powers and Roots

Powers and roots appear in geometric formulas (areas, volumes) and in electrical calculations.

Key Rules:

aᵐ × aⁿ = aᵐ⁺ⁿ

aᵐ ÷ aⁿ = aᵐ⁻ⁿ

(aᵐ)ⁿ = aᵐⁿ

a⁰ = 1

a⁻ⁿ = 1/aⁿ

Square Roots: The square root (√) is the inverse operation of squaring. It appears in formulas such as:

Area of a circle: A = πr², therefore r = √(A/π)

Electrical power: P = I²R, therefore I = √(P/R)

4. Geometry

4.1 Plane Geometry

4.1.1 Triangles

The sum of the interior angles of any triangle is always 180°.

Worked Example:

Two angles of a triangle are 45° and 60°. Find the third angle.

Third angle = 180° − (45° + 60°) = 180° − 105° = 75°

Types of Triangles:

Equilateral: All sides equal, all angles 60°

Isosceles: Two sides equal, two angles equal

Scalene: All sides and angles different

Right-angled: One angle equals 90°

Pythagorean Theorem: In a right-angled triangle, a² + b² = c², where c is the hypotenuse (the side opposite the right angle).

4.1.2 Quadrilaterals

Rectangle: Area = length × width; Perimeter = 2(length + width)

Square: Area = side²; Perimeter = 4 × side

Parallelogram: Area = base × height

Trapezium: Area = ½(a + b) × height, where a and b are the parallel sides

4.1.3 Circles

Key Properties:

Diameter (d) = 2 × radius (r)

Circumference = π × d = 2πr

Area = πr² = πd²/4

Worked Example — Cross-Sectional Area of a Hydraulic Pipe:

Inner diameter = 12 mm, radius = 6 mm

Area = πr² = 3.142 × 6² = 3.142 × 36 = 113.112 mm² ≈ 113.1 mm²

4.2 Solid Geometry

4.2.1 Cylinders

A cylinder is defined by its radius (r) and height or length (h).

Volume = πr²h

Curved surface area = 2πrh

Total surface area = 2πr² + 2πrh

Worked Example — Cylindrical Fuel Tank:

Diameter = 0.6 m, therefore radius = 0.3 m

Length = 1.5 m

Volume = π × r² × h = 3.14 × (0.3)² × 1.5

Volume = 3.14 × 0.09 × 1.5 = 0.4239 m³ ≈ 0.424 m³

4.2.2 Other Solid Shapes

Rectangular prism (box): Volume = length × width × height

Cube: Volume = side³

Sphere: Volume = 4/3 × πr³; Surface area = 4πr²

Cone: Volume = 1/3 × πr²h

Pyramid: Volume = 1/3 × base area × height

4.3 Angles and Angular Measurement

Angles are measured in degrees (°) or radians (rad). A full circle = 360° = 2π radians.

Angle Relationships:

Complementary angles sum to 90°

Supplementary angles sum to 180°

Vertically opposite angles are equal

Corresponding angles (parallel lines cut by a transversal) are equal

Alternate angles (parallel lines cut by a transversal) are equal

5. Statistics

5.1 Arithmetic Mean (Average)

The mean is the sum of all values divided by the number of values. It is used in:

Quality control measurements

Determining average wear or clearance

Analysing repeated measurements

Worked Example — Mean of Measurements:

Five measurements of a component: 12.5 mm, 12.7 mm, 12.6 mm, 12.4 mm, 12.8 mm

Sum = 12.5 + 12.7 + 12.6 + 12.4 + 12.8 = 63.0 mm

Mean = 63.0 ÷ 5 = 12.6 mm

5.2 Median and Mode

Median: The middle value when data is arranged in ascending order. If there is an even number of values, the median is the mean of the two middle values.

Mode: The value that occurs most frequently.

5.3 Range

The range is the difference between the largest and smallest values in a data set. It provides a simple measure of spread or variability.

6. Applied Formulas in Aircraft Maintenance

6.1 Electrical Formulas

These formulas are fundamental to Module 3 (Electrical Fundamentals) but require the algebraic skills from Module 1.

Ohm's Law: V = I × R

V = voltage (volts, V)

I = current (amperes, A)

R = resistance (ohms, Ω)

Electrical Power:

P = V × I

P = I² × R

P = V²/R

Worked Example — Power Dissipation:

A component has a resistance of 4 Ω and a current of 3 A.

P = I² × R = 3² × 4 = 9 × 4 = 36 W

Resistors in Series: R_total = R₁ + R₂ + R₃ + ...

Resistors in Parallel: 1/R_total = 1/R₁ + 1/R₂ + 1/R₃ + ...

6.2 Weight and Balance Formulas

Weight and balance calculations are critical for airworthiness and are performed for every aeroplane.

Moment: Moment = Mass × Distance from datum

Centre of Gravity: CG = Total moment / Total weight

Worked Example — Moment Calculation:

Distance from datum to CG = 2.5 m, total mass = 1,200 kg

Moment = 1,200 kg × 2.5 m = 3,000 kg·m

6.3 Torque Calculations

Torque is the rotational equivalent of force and is critical for fastener installation.

Torque: T = F × d

T = torque (N·m or lb·ft)

F = force (N or lb)

d = perpendicular distance from pivot point (m or ft)

Unit Conversions for Torque:

1 N·m = 0.7376 lb·ft

1 lb·ft = 1.3558 N·m

1 kgf·m = 9.80665 N·m

Worked Example — Imperial to SI Torque Conversion:

AMM specifies 120 lbf·ft. Convert to N·m.

120 × 1.3558 = 162.696 ≈ 162.7 N·m

Worked Example — kgf·m to N·m Conversion:

Torque value of 3.5 kgf·m.

3.5 × 9.80665 = 34.323 ≈ 34.32 N·m

7. Common Relationships Between Concepts

7.1 Algebra ↔ Geometry

Geometric formulas are algebraic expressions. The ability to rearrange these formulas is essential. For example:

Given the area of a circle, find the radius: r = √(A/π)

Given the volume of a cylinder, find the height: h = V/(πr²)

7.2 Arithmetic ↔ Statistics

Statistical calculations are extensions of basic arithmetic. The mean is simply a division problem; the range is a subtraction problem.

7.3 Units ↔ Formulas

All formulas require consistent units. Mixing SI and imperial units in a single calculation will produce incorrect results. Always convert to a consistent system before performing calculations.

7.4 Fractions ↔ Electrical Formulas

Parallel resistance calculations require facility with fractions and reciprocals. Understanding how to add fractions with different denominators is essential for these calculations.

8. Typical Exam Focus Points

Based on the Part-66 Category A (Piston Engine) examination pattern, candidates should focus on:

215.Unit conversions — particularly torque (N·m ↔ lb·ft ↔ kgf·m) and fuel volumes (litres ↔ imperial gallons). These appear frequently and require memorisation of conversion factors.

216.Basic algebraic manipulation — solving linear equations and rearranging formulas. Candidates must be comfortable solving for any variable in a formula.

217.Geometric calculations — areas of circles and volumes of cylinders are the most commonly tested. Remember that radius = diameter/2.

218.Electrical power and resistance calculations — P = I²R and parallel resistance formulas appear regularly, even in Module 1 examinations.

219.Weight and balance calculations — moment = mass × distance, and CG = total moment / total weight.

220.Mean (average) calculations — simple arithmetic mean of a data set.

221.Angle calculations in triangles — the sum of interior angles = 180°.

222.Metric conversions — particularly metres to millimetres and vice versa, as these are used constantly in dimensional measurements.

9. Regulatory References

The mathematical content of Module 1 is defined in:

Regulation (EU) No 1321/2014, Annex III (Part-66), Appendix I — Basic Knowledge Syllabus, Module 1: Mathematics

AMC to Part-66 — Acceptable Means of Compliance providing guidance on examination standards and knowledge level requirements

GM to Part-66 — Guidance Material explaining the intent of the knowledge level definitions

The knowledge levels for Category A require:

Level 1 (for arithmetic and statistics): Familiarisation with basic concepts

Level 2 (for algebra and geometry): General knowledge with the ability to apply formulas and perform calculations

10. Summary

Module 1 Mathematics provides the essential computational toolkit for aircraft maintenance certifying staff. The practical application of these skills extends to every aspect of maintenance activity:

Reading and interpreting maintenance manuals requires understanding of units, formulas, and algebraic notation

Performing weight and balance calculations requires arithmetic and algebraic skills

Applying torque values requires unit conversion proficiency

Understanding electrical systems requires facility with formulas and fractions

Measuring components requires geometric knowledge and statistical analysis

Mastery of these fundamental mathematical skills ensures that certifying staff can perform their duties accurately, safely, and in compliance with EASA regulations. The ability to perform calculations correctly and to verify results independently is a hallmark of professional competence in aircraft maintenance.

Module 1: Mathematics