A — Line Maintenance (Aeroplane Piston)Module 3 · 20 practice questions

Module 3: Electrical Fundamentals

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Semiconductors and Diodes SEMICONDUCTORS AND DIODES PN JUNCTION DIODE — BIAS CONDITIONS P-TYPE (Hole majority) DEPLE- TION REGION N-TYPE (Electron majority) + + + ANODE (A) CATHODE (K) I FORWARD BIAS Conducts current I=0 REVERSE BIAS Blocks current DIODE SYMBOLS Standard: A → K LED: Light emitting HALF-WAVE RECTIFIER CIRCUIT AC 230 V 12 V R V_OUT INPUT (AC) OUTPUT (DC) KEY POINTS • Diode conducts in forward bias • Blocks in reverse bias • Half-wave rectifier uses 1 diode • Converts AC to pulsating DC SILICON DIODE Forward voltage drop ≈ 0.7 V Germanium ≈ 0.3 V EASA Part-66 Module 3 — Electrical Fundamentals | Semiconductors and Diodes

Module 3: Electrical Fundamentals

1. Overview

This module provides the essential theoretical foundation for all aircraft electrical systems. It covers the principles of electron theory, static electricity, and the fundamental concepts of DC and AC circuits. A thorough understanding of these principles is critical for the certifying staff, as it underpins the safe diagnosis, repair, and certification of electrical installations on aircraft. The syllabus is structured to build from basic atomic structure to complex circuit analysis, ensuring a technician can not only perform calculations but also understand the physical behaviour of electrical components under various operating conditions.

2. Key Concepts Explained in Detail

2.1 Electron Theory and Conductors

All matter is composed of atoms, which consist of a central nucleus (containing protons and neutrons) surrounded by orbiting electrons. Electrons in the outermost shell, known as valence electrons, are loosely bound and can be easily displaced. The movement of these free electrons constitutes an electric current.

  • Conductors: Materials with a large number of free electrons (e.g., copper, aluminium, silver) readily allow current flow.
  • Insulators: Materials with very few free electrons (e.g., rubber, glass, PTFE) resist current flow.
  • Semiconductors: Materials (e.g., silicon, germanium) whose conductivity lies between that of conductors and insulators and can be precisely controlled through doping.

2.2 Ohm's Law and Electrical Quantities

Ohm's Law is the fundamental relationship in electrical circuits, defining the relationship between voltage, current, and resistance. It is the cornerstone of all circuit analysis and troubleshooting.

  • Voltage (V): The electrical potential difference between two points, measured in volts (V). It is the "pressure" that pushes electrons through a circuit.
  • Current (I): The rate of flow of electric charge, measured in amperes (A). It is the "flow rate" of electrons.
  • Resistance (R): The opposition to current flow, measured in ohms (Ω). It is the "friction" that impedes the flow.

Ohm's Law Formula:

$$V = I \times R$$

This formula can be rearranged to find current or resistance:

$$I = \frac{V}{R}$$

$$R = \frac{V}{I}$$

Application in Aircraft Systems: In a 28 V DC system, a load drawing 10 A through a cable with a total resistance of 0.1 Ω will experience a voltage drop of 1 V (V = 10 A × 0.1 Ω). The voltage at the load will be 27 V, not the full 28 V. This principle is critical for understanding why loads may not operate at their rated voltage and for diagnosing under-voltage conditions.

2.3 Resistance, Resistivity, and Cable Calculations

The resistance of a conductor is not arbitrary; it depends on its physical properties and dimensions. The resistivity (ρ) is a material-specific property that quantifies how strongly a material opposes current flow.

Resistance Formula:

$$R = \rho \times \frac{L}{A}$$

Where:

  • R = Resistance (Ω)
  • ρ = Resistivity of the material (Ω·m)
  • L = Length of the conductor (m)
  • A = Cross-sectional area of the conductor (m²)

Example Calculation: A copper bonding strap with a cross-sectional area of 2 mm² (2 × 10⁻⁶ m²) and a length of 0.5 m has a resistivity of 1.7 × 10⁻⁸ Ω·m. Its resistance is calculated as:

$$R = 1.7 \times 10^{-8} \times \frac{0.5}{2 \times 10^{-6}} = 0.00425 \, \Omega$$

This formula is essential for verifying the integrity of bonding straps, calculating voltage drops in long wire runs, and understanding why cable size is critical in high-current circuits.

2.4 Electrical Power

Power is the rate at which electrical energy is converted into another form of energy (e.g., heat, light, mechanical work). It is measured in watts (W).

Power Formulas:

$$P = V \times I$$

$$P = I^2 \times R$$

$$P = \frac{V^2}{R}$$

Application: A navigation light rated at 28 W operating on a 14 V DC system draws a current of:

$$I = \frac{P}{V} = \frac{28 \text{ W}}{14 \text{ V}} = 2 \text{ A}$$

This calculation is fundamental for verifying that circuit protection devices are correctly rated. A 5 A circuit breaker provides adequate protection for this 2 A load without nuisance tripping.

Basic Electrical Circuits Basic Electrical Circuits Series vs Parallel — Ohm's Law Application — EASA Part-66 Module 3 SERIES CIRCUIT V=28V + R1=4Ω R2=6Ω R3=10Ω I = 2A (same everywhere) Key Facts: • Current: Same through all components (I = I₁ = I₂ = I₃) • Voltage: Divided among components (V = V₁ + V₂ + V₃) • Total Resistance: R_total = R₁ + R₂ + R₃ = 4 + 6 + 10 = 20Ω PARALLEL CIRCUIT V=28V + R1=10Ω R2=20Ω R3=40Ω I=2.8A I=1.4A I=0.7A I_total = 4.9A Key Facts: • Voltage: Same across all branches (V = V₁ = V₂ = V₃ = 28V) • Current: Divided among branches (I = I₁ + I₂ + I₃) • Total Resistance: 1/R_total = 1/R₁ + 1/R₂ + 1/R₃ = 0.1+0.05+0.025 → R_total ≈ 5.7Ω COMPARISON & OHM'S LAW APPLICATION Property Series Circuit Parallel Circuit Current (I) Same everywhere: I = V / R_total Divided: I_total = I₁ + I₂ + I₃ Voltage (V) Divided: V_total = V₁ + V₂ + V₃ Same across all branches: V = V₁ = V₂ = V₃ Resistance (R) R_total = R₁ + R₂ + R₃ = 20Ω 1/R_total = 1/R₁ + 1/R₂ + 1/R₃ ≈ 5.7Ω Ohm's Law V = I × R → 28V = 2A × 14Ω I = V/R → 4.9A = 28V / 5.7Ω Example Values V₁=8V, V₂=12V, V₃=20V (sums to 28V) I₁=2.8A, I₂=1.4A, I₃=0.7A (sums to 4.9A) Ohm's Law: V = I × R | Power: P = V × I | Kirchhoff's Laws apply for complex circuits

2.5 Series and Parallel Circuits

Understanding how components are connected is crucial for circuit analysis.

  • Series Circuit: Components are connected end-to-end, providing a single path for current flow.
  • Total Resistance: $R_{total} = R_1 + R_2 + R_3 + \dots$
  • Current is the same through all components.
  • Voltage is divided among components (Kirchhoff's Voltage Law).
  • Parallel Circuit: Components are connected across the same two points, providing multiple paths for current flow.
  • Total Resistance: $\frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \dots$
  • Voltage is the same across all branches.
  • Current is divided among branches (Kirchhoff's Current Law).

Application to Starter Motor Circuit: A battery with an internal resistance of 0.01 Ω connected to a starter motor via a cable with 0.02 Ω resistance forms a series circuit. The total resistance is 0.03 Ω. When the starter draws 200 A, the total voltage drop is 6 V (V = 200 A × 0.03 Ω). The voltage available at the starter terminals is therefore 24 V – 6 V = 18 V. This demonstrates the combined effect of internal and cable resistance on system performance.

2.6 Kirchhoff's Laws

Kirchhoff's laws are extensions of Ohm's law for analysing complex circuits.

  • Kirchhoff's Current Law (KCL): The algebraic sum of currents entering a node (junction) is zero. In other words, the total current entering a junction equals the total current leaving it.
  • Kirchhoff's Voltage Law (KVL): The algebraic sum of all voltages around any closed loop in a circuit is zero. This is a restatement of the law of conservation of energy.

These laws are fundamental for analysing circuits with multiple loops and branches, such as those found in complex aircraft systems.

2.7 The Wheatstone Bridge

The Wheatstone bridge is a specific circuit configuration used for precise resistance measurements and is commonly found in aircraft sensors and indicators (e.g., fuel quantity, position indicators).

It consists of four resistors arranged in a diamond shape with a voltage source connected across one diagonal and a galvanometer (or voltage measuring device) across the other.

Balanced Condition: The bridge is balanced when the ratio of the resistances in the two arms is equal:

$$\frac{R_1}{R_2} = \frac{R_3}{R_4}$$

When balanced, the voltage across the galvanometer is zero, and no current flows through it.

Unbalanced Condition: If any resistance changes (e.g., a sensor resistance changes due to movement or a loose connection), the bridge becomes unbalanced. A voltage difference appears across the galvanometer, which can be measured and interpreted.

Application in Landing Gear Indication: A position indicator uses two resistive sensors in a Wheatstone bridge. When the gear is down, the bridge is balanced. If a sensor's resistance increases due to a loose connection, the bridge becomes unbalanced, producing a non-zero output voltage. The control unit interprets this voltage as a change in position, potentially showing "in transit" or "up" even when the gear is physically down. This is a classic failure mode that technicians must be able to diagnose.

2.8 Circuit Protection Devices

Circuit protection devices are critical for safety, preventing wire overheating and potential fires.

  • Fuses: A thin wire or strip that melts and breaks the circuit when current exceeds its rated value. They are one-time-use devices and must be replaced after operation.
  • Circuit Breakers: Electromechanical devices that trip (open the circuit) when current exceeds a specified value. They can be reset and reused.

Selection Criteria: A protection device must be rated above the normal operating current to avoid nuisance trips but low enough to protect the circuit from overloads and short circuits.

Example: An electric fuel pump draws 4 A continuously with a startup surge of 6 A for 2 seconds. A 5 A fuse is the appropriate choice. It is above the normal operating current (4 A) to prevent nuisance trips, can handle the brief 6 A surge, and will protect the circuit from sustained overloads. A 10 A fuse would not provide adequate protection for a 4 A load.

Short Circuit Effects: A direct short to ground creates a very low resistance path, causing a large current flow (I = V/R). Without protection, this can rapidly overheat the wire and cause a fire. This is why circuit protection is mandatory on all aircraft electrical circuits.

2.9 Batteries and Electrochemistry

Batteries are electrochemical devices that convert chemical energy into electrical energy. The lead-acid battery is the most common type used in piston-engine aircraft.

Lead-Acid Cell Chemistry:

  • Positive Plate: Lead dioxide (PbO₂)
  • Negative Plate: Sponge lead (Pb)
  • Electrolyte: Sulphuric acid (H₂SO₄) and distilled water

Discharge: During discharge, both plates convert to lead sulphate (PbSO₄), and the electrolyte becomes weaker (specific gravity decreases) as sulphuric acid is consumed.

Charge: During charging, the process is reversed. Lead sulphate is converted back to lead and lead dioxide, and sulphuric acid is regenerated, increasing the specific gravity of the electrolyte.

Cell Voltages:

  • Nominal Voltage: 2.0 V per cell
  • Fully Charged Open-Circuit Voltage: Approximately 2.1 V per cell

Battery Configurations:

  • 12 V Battery: 6 cells in series, giving a nominal voltage of 12 V and a fully charged open-circuit voltage of approximately 12.6 V.
  • 24 V Battery: 12 cells in series, giving a nominal voltage of 24 V and a fully charged open-circuit voltage of approximately 25.2 V.

Key Measurement Points:

  • A reading of 12.0 V on a "12 V" battery indicates a partially discharged state (approximately 50% state of charge).
  • A reading of 11.8 V indicates a nearly discharged battery.
  • A reading of 13.8 V is a charging voltage, not an open-circuit voltage.

2.10 Electrical Measurement Techniques

Accurate measurement is essential for troubleshooting. The following principles apply:

Voltage Measurement:

  • A voltmeter is connected in parallel across the component or circuit being measured.
  • The circuit must be energised for voltage measurements.

Current Measurement:

  • An ammeter is connected in series with the circuit.
  • The circuit must be energised for current measurements.
  • Clamp-on Ammeter: Measures current without breaking the circuit by sensing the magnetic field around a conductor. To obtain an accurate reading, the clamp must be placed around only one conductor (supply or return), as clamping around both would result in the magnetic fields cancelling out.
  • Digital Multimeter (DMM): When measuring current, the meter must be set to the appropriate range. For currents exceeding the mA range (e.g., 7.14 A for a 100 W landing light on a 14 V system), the dedicated 10 A jack must be used. Connecting an ammeter in parallel creates a short circuit and is dangerous.

Resistance Measurement:

  • An ohmmeter is connected in parallel across the component.
  • The circuit must be de-energised (power removed) before measuring resistance. This prevents damage to the meter and ensures accurate readings.
  • The component should be isolated from the rest of the circuit to avoid parallel paths that would give false readings.

3. Important Formulas and Regulations

3.1 Key Formulas

QuantityFormulaUnits
Ohm's LawV = I × RV, A, Ω
PowerP = V × I = I² × R = V²/RW
Resistance (physical)R = ρ × (L / A)Ω
Resistivityρ = (R × A) / LΩ·m
Series ResistanceR_total = R₁ + R₂ + R₃ + ...Ω
Parallel Resistance1/R_total = 1/R₁ + 1/R₂ + 1/R₃ + ...Ω

3.2 Regulatory References

  • Regulation (EU) No 1321/2014, Annex III (Part-66): This regulation establishes the requirements for the certification of maintenance staff. Module 3 of Appendix I defines the basic knowledge requirements for Electrical Fundamentals.
  • Knowledge Levels: The syllabus defines three levels of knowledge:
  • Level 1: An overview of the subject. The technician can recall basic facts and understand the general principles.
  • Level 2: General knowledge. The technician can understand the theory and apply it to simple calculations and troubleshooting.
  • Level 3: Detailed theory. The technician has a deep understanding of the subject and can analyse complex systems and diagnose faults.

4. Common Relationships Between Concepts

  • Voltage, Current, and Resistance: Ohm's law (V = I × R) shows that for a fixed resistance, an increase in voltage will cause a proportional increase in current. For a fixed voltage, an increase in resistance will cause a decrease in current.
  • Power and Current: Power (P = V × I) is directly proportional to current. A higher-power load will draw more current at a given voltage.
  • Resistance and Physical Dimensions: Resistance is directly proportional to length and inversely proportional to cross-sectional area. A longer, thinner wire has more resistance than a shorter, thicker wire of the same material.
  • Battery State of Charge and Specific Gravity: The specific gravity of the electrolyte is directly related to the state of charge. A fully charged battery has a high specific gravity, while a discharged battery has a low specific gravity.
  • Circuit Protection and Current: The rating of a fuse or circuit breaker must be matched to the expected current draw of the circuit. An undersized protection device will nuisance-trip, while an oversized one will not protect the circuit from damage.
  • Internal Resistance and Voltage Drop: All voltage sources (batteries, generators) have internal resistance. When current flows, this internal resistance causes a voltage drop, reducing the voltage available at the terminals. This is why the voltage at the starter motor terminals is lower than the battery's open-circuit voltage during cranking.

5. Typical Exam Focus Points

Based on the source questions, the following areas are frequently tested:

  • Ohm's Law Calculations: Be able to calculate voltage, current, or resistance given the other two quantities. Pay attention to units (e.g., convert mm² to m²).
  • Voltage Drop in Cables: Understand that cables have resistance and that this causes a voltage drop, reducing the voltage available at the load. Remember to account for both supply and return conductors.
  • Power Calculations: Be able to calculate current from power and voltage (I = P/V) and understand the implications for circuit protection.
  • Battery Characteristics: Know the nominal and fully charged open-circuit voltages for lead-acid cells and batteries (2.0 V and 2.1 V per cell). Understand the relationship between specific gravity and state of charge.
  • Circuit Protection Selection: Understand how to select the correct fuse or circuit breaker rating based on normal operating current and surge currents.
  • Wheatstone Bridge: Understand the balanced condition and what happens when the bridge becomes unbalanced.
  • Measurement Techniques: Know the correct way to connect a voltmeter (parallel), ammeter (series), and ohmmeter (de-energised circuit). Understand the use of clamp-on ammeters.
  • Short Circuit Effects: Understand the consequences of a direct short to ground and the importance of circuit protection.
  • Resistance Formula: Be able to calculate resistance, resistivity, length, or cross-sectional area using R = ρ × (L / A).
  • Series Circuits: Understand how to calculate total resistance and voltage drops in series circuits, including internal resistance of sources.

Practice this module

Reinforce Module 3: Electrical Fundamentals with 20 EASA-style practice questions, matched to your weak areas.